WebExpert Answer. 100% (5 ratings) Transcribed image text: (a) How many ways can the letters of the word MAILBOX be arranged in a row? (b) How many ways can the letters of the word MAILBOX be arranged in a row if M and A must remain together (in order) as a unit? (c) How many ways can the letters of the word MAILBOX be arranged in a row if … WebA permutation of some number of objects means the collection of all possible arrangements of those objects. Enter your objects (or the names of them), one per line in the box below, then click "Show me!" to see how many ways they can be arranged, and what those arrangements are. Note: 8 items have a total of 40,320 different combinations.
Solved (a) How many ways can the letters of the word MAILBOX …
WebExercise : Permutation and Combination - General Questions. 11. In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women? = 63. 12. How many 4-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHMS', if repetition of letters is not allowed? = Number of arrangements of ... Web12 nov. 2024 · How many ways to arrange 7 letters in Algebra? 2520 is the number of ways to arrange 7 letters (alphabets) word “ALGEBRA” by using Permutations (nPr) … side high knee
How many different ways can you arrange 7 objects?
Web21 feb. 2024 · The word EXTRA can be arranged in 5! ways = 120 ways The word EXTRA can be arranged in such a way that the vowels will be together = 4! × 2! ⇒ (4 × 3 × 2 × 1) × (2 × 1) ⇒ 48 ways The letters of the words EXTRA be arranged so that the vowels are never together = (120 - 48) = 72 ways. Web28 mrt. 2024 · Here number of letters in word arise is 5 Different ways in which arise can be arranged is 5! 5! = 5 × 4 × 3 × 2 × 1 5! = 120 ∴ The way of arrange of the word ARISE is 120. Download Solution PDF Share on Whatsapp Latest DFCCIL Executive Updates Last updated on Oct 25, 2024 Web13 nov. 2024 · Thus, there are all together 6 letters and they can be arranged by 6! ways. But 3 vowels can be arranged to each other by 3! ways. Hence, By multiplication principle of counting:-. Total required ways = 6! * 3! = 4320. b) Vowels may occupy only an odd position. Clearly, there are 4 odd positions and 3 vowels. Thus, 3 vowels can be … the planet with a ring